[๋ฐฑ์ค€-1916] ์ตœ์†Œ๋น„์šฉ ๊ตฌํ•˜๊ธฐ / Python

๐Ÿ“š Problem Solving/Baekjoon

 

1916๋ฒˆ: ์ตœ์†Œ๋น„์šฉ ๊ตฌํ•˜๊ธฐ

์ฒซ์งธ ์ค„์— ๋„์‹œ์˜ ๊ฐœ์ˆ˜ N(1 ≤ N ≤ 1,000)์ด ์ฃผ์–ด์ง€๊ณ  ๋‘˜์งธ ์ค„์—๋Š” ๋ฒ„์Šค์˜ ๊ฐœ์ˆ˜ M(1 ≤ M ≤ 100,000)์ด ์ฃผ์–ด์ง„๋‹ค. ๊ทธ๋ฆฌ๊ณ  ์…‹์งธ ์ค„๋ถ€ํ„ฐ M+2์ค„๊นŒ์ง€ ๋‹ค์Œ๊ณผ ๊ฐ™์€ ๋ฒ„์Šค์˜ ์ •๋ณด๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. ๋จผ์ € ์ฒ˜์Œ์—๋Š” ๊ทธ

www.acmicpc.net

import sys
import heapq

INF = int(1e9)
n = int(input())
m = int(input())
graph = [[] for _ in range(n + 1)]
distance = [INF] * (n + 1)

for _ in range(m):
    a, b, c = map(int, input().split())
    graph[a].append((b, c))

start, end = map(int, input().split())


def dijkstra(start):
    q = []
    heapq.heappush(q, (0, start))
    distance[start] = 0
    while q:
        dist, now = heapq.heappop(q)
        if distance[now] < dist:
            continue
        for i in graph[now]:
            cost = dist + i[1]
            if cost < distance[i[0]]:
                distance[i[0]] = cost
                heapq.heappush(q, (cost, i[0]))


dijkstra(start)

print(distance[end])

 

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