[๋ฐฑ์ค€-1753] ์ตœ๋‹จ๊ฒฝ๋กœ / Python

๐Ÿ“š Problem Solving/Baekjoon

https://www.acmicpc.net/problem/1753

 

1753๋ฒˆ: ์ตœ๋‹จ๊ฒฝ๋กœ

์ฒซ์งธ ์ค„์— ์ •์ ์˜ ๊ฐœ์ˆ˜ V์™€ ๊ฐ„์„ ์˜ ๊ฐœ์ˆ˜ E๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1≤V≤20,000, 1≤E≤300,000) ๋ชจ๋“  ์ •์ ์—๋Š” 1๋ถ€ํ„ฐ V๊นŒ์ง€ ๋ฒˆํ˜ธ๊ฐ€ ๋งค๊ฒจ์ ธ ์žˆ๋‹ค๊ณ  ๊ฐ€์ •ํ•œ๋‹ค. ๋‘˜์งธ ์ค„์—๋Š” ์‹œ์ž‘ ์ •์ ์˜ ๋ฒˆํ˜ธ K(1≤K≤V)๊ฐ€ ์ฃผ์–ด์ง„๋‹ค.

www.acmicpc.net

import sys
import heapq

INF = int(1e9)
V, E = map(int, sys.stdin.readline().split())
k = int(sys.stdin.readline())
graph = [[] for _ in range(V + 1)]
distance = [INF] * (V + E)

for _ in range(E):
    u, v, w = map(int, input().split())
    graph[u].append((v, w))


def dijkstra(start):
    q = []
    heapq.heappush(q, (0, start))
    distance[start] = 0
    while q:
        dist, now = heapq.heappop(q)
        if distance[now] < dist:
            continue
        for i in graph[now]:
            cost = dist + i[1]
            if cost < distance[i[0]]:
                distance[i[0]] = cost
                heapq.heappush(q, (cost, i[0]))


dijkstra(k)
for i in range(1, V + 1):
    if distance[i] == INF:
        print("INF")
    else:
        print(distance[i])

 

ํ•ด์„ค

์–ด์ œ ์ด์ทจ์ฝ” ์ฑ…์—์„œ ๋ณต์Šตํ–ˆ๋˜ ๋‹ค์ต์ŠคํŠธ๋ผ ๋ฌธ์ œ์™€ ๊ฐ™๋‹ค. ์–ด์ œ ๋ณต์Šตํ•œ ๋•๋ถ„์— ์ˆ˜์›”ํ•˜๊ฒŒ ํ•ด๊ฒฐํ–ˆ๋‹ค !๐Ÿ˜€