[λ°±μ€-1780] μ’
μ΄μ κ°μ / Python
π Problem Solving/Baekjoon
1780λ²: μ’ μ΄μ κ°μ
N×Nν¬κΈ°μ νλ ¬λ‘ ννλλ μ’ μ΄κ° μλ€. μ’ μ΄μ κ° μΉΈμλ -1, 0, 1μ μΈ κ° μ€ νλκ° μ μ₯λμ΄ μλ€. μ°λ¦¬λ μ΄ νλ ¬μ μ μ ν ν¬κΈ°λ‘ μλ₯΄λ €κ³ νλλ°, μ΄λ λ€μμ κ·μΉμ λ°λΌ μλ₯΄λ €κ³ νλ€.
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import sys
n = int(sys.stdin.readline())
paper = [list(map(int, sys.stdin.readline().split())) for _ in range(n)]
minusOne, zero, one = 0, 0, 0
def divide(n, x, y):
global minusOne, zero, one
num = paper[x][y]
for i in range(x, x + n):
for j in range(y, y + n):
if num != paper[i][j]:
for k in range(3):
for l in range(3):
divide(n // 3, x + k * n // 3, y + l * n // 3)
return
if num == -1:
minusOne += 1
elif num == 0:
zero += 1
else:
one += 1
divide(n, 0, 0)
print(minusOne)
print(zero)
print(one)
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μμ§ μ¬κ· λ¬Έμ λ₯Ό νΈλλ° μ‘°κΈμ© μ΄λ €μμ λλλ€..π
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